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The shaft of a circular cross-section is loaded by torsion moments. Under condition of strength and torsion condition of rigidity of the shaft select the diameter of the shaft.
Draw diagrams of twisting moments, the greatest values of shear stresses and twisting angles along the shaft.
assume the allowable value of normal stress [ s ] = 160 MPа for shaft material. Take the data necessary for computation from table 4 and shaft scheme from fig.3.
Table 4
| variant /group No./ | ||||||||||
| Mt, kN m | ||||||||||
| a, m | 1.1 | 1.2 | 1.3 | 1.4 | 1.5 | 1.6 | 0.7 | 0.8 | 0.9 | 1.5 |
| q, o/m | 0,21 | 0,22 | 0,23 | 0,24 | 0,25 | 0,06 | 0,07 | 0,08 | 0,09 | 0,16 |
Order of work
1. Draw the scheme of the shaft to scale.
2. From the condition of balance determine the moment at the fixed end or moment М 0.
3. Using the method of section determine value of the twisting moments on each section of the shaft and draw the diagram.
4. According to the properties of the shaft material determine allowable value of shear stress.
5. determine diameter of the shaft by condition of strength in torsion.
6. determine diameter of the shaft by condition of rigidity in torsion. Finаlly choose the greatest value from two diameters which approximate to the nearest standard magnitude.
7. Determine the greatest value of shear stresses on the each chosen section of the shaft. Draw the diagram of maximum shear stresses.
8. Determine the value of the angles of twisting for each section of the shaft and draw the diagram of the angles.
9. check up rigidity of the shaft and make the conclusions.
Fig. 3. (see also p.11)
Fig. 3. Continued (see also p.12)
Fig.3. Ending
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