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K=3
l= 
=3833
| x | f | S | |
= 
+ 
=3500+3833 
= 2411,46
=3500
=3833
=5
=0
=2
Figure 5. Histogram for finding the mode in the interval variational series of distribution of prices of dental services
= 
=3500+3833 
=7333
= 
= 
=5
=3500
=3833
=0
=5
Figure 6. Cumulative frequency polygon for finding the median in the interval variational series of distribution of prices of dental services.
Calculation the variance, standard deviation and coefficient of variation. Conclusions about the homogeneity of the studied population and the typicality of the arithmetic mean.
| x | f | x-x average | (x-x average)2 | (x-x average)2*f |
| -5350 | ||||
| -3850 | ||||
| -2850 | ||||
| -1850 | ||||
| Total |
x̅=8850
= 
= 
=14891666,67
Standard deviation
S= 
2 = 
=3858,9722
Coefficient of variation
ʋ= 
*100%= 
*100%=43,60421%
Conclusion
In my research “How much money do people spend on dental service?” these calculations above show that the sample is non homogeneous, x̅ is not typical because the coefficient equals 43,6% and it is more than 33%
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